A \green{L2 \times W2}
rectangle
sits inside a \blue{L1 \times W1}
rectangle.
What is the area of the shaded region?
First, calculate the area of the whole figure, including the unshaded area.
The area of a rectangle is the length times the width.
\qquad \blue{L1 \times W1 = A1}
Next, calculate the area of the inner figure.
\qquad \green{L2 \times W2 = A2}
Finally, subtract the area of the inner rectangle from the area of the outer rectangle.
\qquad \blue{A1} - \green{A2} = A1 - A2
A circle with radius of \green{R2}
sits inside a circle with radius of \blue{R1}
.
What is the area of the shaded region?
First, calculate the area of the whole figure, including the unshaded area.
The area of a circle is \pi r^2
.
\qquad \blue{\pi \times R1 \times R1 = A1\pi}
Next, calculate the area of the inner figure.
\qquad \green{\pi \times R2 \times R2 = A2\pi}
Finally, subtract the area of the inner circle from the area of the outer circle.
\qquad \blue{A1\pi} - \green{A2\pi} = A1 - A2\pi
A circle with radius of \green{R}
sits inside a \blue{L \times W}
rectangle.
What is the area of the shaded region?
Round to the nearest hundredth.
First, calculate the area of the whole figure, including the unshaded area.
The area of a rectangle is the length times the width.
\qquad \blue{L \times W = A1}
Next, calculate the area of the inner figure.
The area of a circle is \pi r^2
.
\qquad \green{\pi \times R \times R = A2\pi}
Finally, subtract the area of the inner circle from the area of the outer rectangle.
\qquad \blue{A1} - \green{A2\pi} \approx A
A \green{L \times W}
rectangle sits inside a circle with radius of \blue{R}
.
What is the area of the shaded region?
Round to the nearest hundredth.
First, calculate the area of the whole figure, including the unshaded area.
The area of a circle is \pi r^2
.
\qquad \blue{\pi \times R \times R = A1\pi}
Next, calculate the area of the inner figure.
The area of a rectangle is the length times the width.
\qquad \green{L \times W = A2}
Finally, subtract the area of the inner rectangle from the area of the outer circle.
\qquad \blue{A1\pi} - \green{A2} \approx A