The equation of a circle C is
expr(["+",
"x^2",
"y^2",
D === 0 ? null : ["*", D, "x"],
E === 0 ? null : ["*", E, "y"],
F === 0 ? null : F
]) = 0.
What is its center (h, k) and its radius r?
(h, k) = (H, K)
r = {}R
To find the equation in standard form, complete the square.
(expr(["+", "x^2", ["*", D, "x"]])) + (expr(["+", "y^2", ["*", E, "y"]])) = -F
(expr(["+", "x^2", ["*", D, "x"], H * H])) + (expr(["+", "y^2", ["*", E, "y"], K * K])) = -F + H * H + K * K
X2T + Y2T = R * R = R^2
Thus, (h, k) = (H, K) and r = R.