{Many|All|Several} of person(1)'s friends wanted to try the candy bars
he brought back from his trip, but there were only PIECES candy bars.
person(1) decided to cut the candy bars into pieces so that each person could have
\frac{N}{D} of a candy bar.
{Many|All|Several} of person(1)'s friends wanted to try the candy bars
she brought back from her trip, but there were only PIECES candy bars.
person(1) decided to cut the candy bars into pieces so that each person could have
\frac{N}{D} of a candy bar.
After cutting up the candy bars, to how many friends could person(1) give his candy, assuming he didn't eat any?
After cutting up the candy bars, to how many friends could person(1) give her candy, assuming she didn't eat any?
We can divide the number of candy bars (PIECES) by the amount person(1) gave to each person
(\frac{N}{D} of a bar) to find out how many people he could give a piece to.
We can divide the number of candy bars (PIECES) by the amount person(1) gave to each person
(\frac{N}{D} of a bar) to find out how many people she could give a piece to.
\dfrac{\red{PIECES \text{ CANDY_BARS}}}
{\blue{\dfrac{N}{D} \text{ BAR_PER_PERSON}}} = \green{\text{ TOTAL_PEOPLE}}
Dividing by a fraction is the same as multiplying by the reciprocal.
The reciprocal of \dfrac{N}{D} \text{ BAR_PER_PERSON}
is \green{\dfrac{D}{N} \text{ PEOPLE_PER_BAR}}.
\red{PIECES\text{ CANDY_BARS}} \times
\green{\dfrac{D}{N} \text{ PEOPLE_PER_BAR}}
= \green{\text{TOTAL_PEOPLE}}
\green{\dfrac{D * PIECES}{N}\text{ PEOPLE}} = SOLUTION\text{ PEOPLE}
By cutting up the candy bars, person(1) could give his candy to SOLUTION of his friends.
By cutting up the candy bars, person(1) could give her candy to SOLUTION of her friends.
person(1) just found beautiful yarn {for randFromArray([5,20]) \% off }at
his favorite yarn store.
He can make one scarf from \frac{N}{D} of a ball of yarn.
person(1) just found beautiful yarn {for randFromArray([5,20]) \% off }at
her favorite yarn store.
She can make one scarf from \frac{N}{D} of a ball of yarn.
If person(1) buys YARN balls of yarn, how many scarves can he make?
If person(1) buys YARN balls of yarn, how many scarves can she make?
We can divide the balls of yarn (YARN) by the yarn needed per scarf
(\frac{N}{D} of a ball) to find out how many scarves person(1) can make.
\dfrac{\red{YARN \text{ BALLS_OF_YARN}}}
{\blue{\dfrac{N}{D} \text{ BALL_PER_SCARF}}} = \green{\text{ NUMBER_OF_SCARVES}}
Dividing by a fraction is the same as multiplying by the reciprocal.
The reciprocal of \blue{\dfrac{N}{D} \text{ BALL_PER_SCARF}}
is \green{\dfrac{D}{N} \text{ SCARVES_PER_BALL}}.
\red{YARN\text{ BALLS_OF_YARN}} \times
\green{\dfrac{D}{N} \text{ SCARVES_PER_BALL}}
= \green{\text{ NUMBER_OF_SCARVES}}
\green{\dfrac{D * YARN}{N}\text{ SCARVES}} = SOLUTION\text{ SCARVES}
person(1) can make SOLUTION scarves.
person(1) decided to paint some of the rooms at his ROOM-room inn,
person(1)'s Place. He discovered he needed \frac{N}{D}
of a can of paint per room.
person(1) decided to paint some of the rooms at her ROOM-room inn,
person(1)'s Place. She discovered she needed \frac{N}{D}
of a can of paint per room.
If person(1) had PAINT cans of paint, how many rooms could he paint?
If person(1) had PAINT cans of paint, how many rooms could she paint?
We can divide the cans of paint (PAINT) by the paint needed per room
(\frac{N}{D} of a can) to find out how many rooms person(1) could paint.
\dfrac{\red{PAINT \text{ CANS_OF_PAINT}}}
{\blue{\dfrac{N}{D} \text{ CAN_PER_ROOM}}} = \blue{\text{ ROOMS}}
Dividing by a fraction is the same as multiplying by the reciprocal.
The reciprocal of \blue{\dfrac{N}{D} \text{ CAN_PER_ROOM}}
is \green{\dfrac{D}{N} \text{ ROOMS_PER_CAN}}.
\red{PAINT\text{ CANS_OF_PAINT}} \times
\green{\dfrac{D}{N} \text{ ROOMS_PER_CAN}}
= \blue{\text{ ROOMS}}
\blue{\dfrac{D * PAINT}{N}\text{ ROOMS}} = SOLUTION\text{ ROOMS}
person(1) could paint SOLUTION rooms.
As the swim coach at school(1), person(1) selects which athletes will participate in the state-wide swim relay.
The relay team swims \frac{A}{B} of a mile in total, with each team
member responsible for swimming \frac{N}{D} of a mile.
The team must complete the swim in \frac{3}{randRange(4,5)} of an hour.
How many swimmers does person(1) need on the relay team?
To find out how many swimmers person(1) needs on the team, divide the total distance
(\frac{A}{B} of a mile) by the distance each team member will swim
(\frac{N}{D} of a mile).
\dfrac{\red{\dfrac{A}{B} \text{ MILE}}}
{\blue{\dfrac{N}{D} \text{ MILE_PER_SWIMMER}}} = \blue{\text{ NUMBER_OF_SWIMMERS}}
Dividing by a fraction is the same as multiplying by the reciprocal.
The reciprocal of \blue{\dfrac{N}{D} \text{ MILE_PER_SWIMMER}}
is \green{\dfrac{D}{N} \text{ SWIMMERS_PER_MILE}}.
\red{\dfrac{A}{B}\text{ MILE}} \times
\green{\dfrac{D}{N} \text{ SWIMMERS_PER_MILE}}
= \blue{\text{ NUMBER_OF_SWIMMERS}}
\dfrac{\red{A} \cdot \green{D}} {\red{B} \cdot \green{N}}
= \blue{\text{ NUMBER_OF_SWIMMERS}}
Reduce terms with common factors by dividing the A in the numerator
and the N in the denominator by GCD1:
\dfrac{\red{\cancel{A}^{SIMP_A}} \cdot \green{D}}
{\red{B} \cdot \green{\cancel{N}^{SIMP_N}}}
= \blue{\text{ NUMBER_OF_SWIMMERS}}
Reduce terms with common factors by dividing the D in the numerator
and the B in the denominator by GCD2:
\dfrac{\red{SIMP_A} \cdot \green{\cancel{D}^{SIMP_D}}}
{\red{\cancel{B}^{SIMP_B}} \cdot \green{SIMP_N}}
= \blue{\text{ NUMBER_OF_SWIMMERS}}
Simplify:
\dfrac{\red{SIMP_A} \cdot \green{SIMP_D}}
{\red{SIMP_B} \cdot \green{SIMP_N}}
= \blue{SOLUTION}
person(1) needs SOLUTION swimmers on his team.
person(1) needs SOLUTION swimmers on her team.
person(1) thought it would be nice to include \frac{N}{D} of a pound of chocolate in each
of the holiday gift bags he made for his friends and family.
person(1) thought it would be nice to include \frac{N}{D} of a pound of chocolate in each
of the holiday gift bags she made for her friends and family.
How many holiday gift bags could person(1) make with \frac{A}{B} of a pound of chocolate?
To find out how many gift bags person(1) could create, divide the total chocolate
(\frac{A}{B} of a pound) by the amount he wanted to include in each gift bag
(\frac{N}{D} of a pound).
To find out how many gift bags person(1) could create, divide the total chocolate
(\frac{A}{B} of a pound) by the amount she wanted to include in each gift bag
(\frac{N}{D} of a pound).
\dfrac{\red{\dfrac{A}{B} \text{ POUND_OF_CHOCOLATE}}}
{\blue{\dfrac{N}{D} \text{ POUND_PER_BAG}}} = \blue{\text{ NUMBER_OF_BAGS}}
Dividing by a fraction is the same as multiplying by the reciprocal.
The reciprocal of \blue{\dfrac{N}{D} \text{ POUND_PER_BAG}}
is \green{\dfrac{D}{N} \text{ BAGS_PER_POUND}}.
\red{\dfrac{A}{B}\text{ POUND}} \times
\green{\dfrac{D}{N} \text{ BAGS_PER_POUND}}
= \blue{\text{ NUMBER_OF_BAGS}}
\dfrac{\red{A} \cdot \green{D}}
{\red{B} \cdot \green{N}}
= \blue{\text{ NUMBER_OF_BAGS}}
Reduce terms with common factors by dividing the A in the numerator
and the N in the denominator by GCD1:
\dfrac{\red{\cancel{A}^{SIMP_A}} \cdot \green{D}}
{\red{B} \cdot \green{\cancel{N}^{SIMP_N}}}
= \blue{\text{ NUMBER_OF_BAGS}}
Reduce terms with common factors by dividing the D in the numerator
and the B in the denominator by GCD2:
\dfrac{\red{SIMP_A} \cdot \green{\cancel{D}^{SIMP_D}}}
{\red{\cancel{B}^{SIMP_B}} \cdot \green{SIMP_N}}
= \blue{\text{ NUMBER_OF_BAGS}}
Simplify:
\dfrac{\red{SIMP_A} \cdot \green{SIMP_D}}
{\red{SIMP_B} \cdot \green{SIMP_N}}
= \blue{SOLUTION}
person(1) could create SOLUTION gift bags.
person(1) works out for \frac{A}{B} of an hour every day. To keep his
exercise routines interesting, he includes different types of exercises, such as
plural_form(exercise(1)) and plural_form(exercise(2)), in each workout.
person(1) works out for \frac{A}{B} of an hour every day. To keep her
exercise routines interesting, she includes different types of exercises, such as
plural_form(exercise(1)) and plural_form(exercise(2)), in each workout.
If each type of exercise takes \frac{N}{D} of an hour, how many different types of
exercise can person(1) do in each workout?
To find out how many types of exercise person(1) could do in each workout, divide
the total amount of exercise time (\frac{A}{B} of an hour) by the amount of
time each exercise type takes (\frac{N}{D} of an hour).
\dfrac{\red{\dfrac{A}{B} \text{ HOUR}}}
{\blue{\dfrac{N}{D} \text{ HOUR_PER_EXERCISE}}} = \blue{\text{ NUMBER_OF_EXERCISES}}
Dividing by a fraction is the same as multiplying by the reciprocal.
The reciprocal of \blue{\dfrac{N}{D} \text{ HOUR_PER_EXERCISE}}
is \green{\dfrac{D}{N} \text{ EXERCISES_PER_HOUR}}.
\red{\dfrac{A}{B}\text{ HOUR}} \times
\green{\dfrac{D}{N} \text{ EXERCISES_PER_HOUR}}
= \blue{\text{ NUMBER_OF_EXERCISES}}
\dfrac{\red{A} \cdot \green{D}}
{\red{B} \cdot \green{N}}
= \blue{\text{ NUMBER_OF_EXERCISES}}
Reduce terms with common factors by dividing the A in the numerator
and the N in the denominator by GCD1:
\dfrac{\red{\cancel{A}^{SIMP_A}} \cdot \green{D}}
{\red{B} \cdot \green{\cancel{N}^{SIMP_N}}}
= \blue{\text{ NUMBER_OF_EXERCISES}}
Reduce terms with common factors by dividing the D in the numerator
and the B in the denominator by GCD2:
\dfrac{\red{SIMP_A} \cdot \green{\cancel{D}^{SIMP_D}}}
{\red{\cancel{B}^{SIMP_B}} \cdot \green{SIMP_N}}
= \blue{\text{ NUMBER_OF_EXERCISES}}
Simplify:
\dfrac{\red{SIMP_A} \cdot \green{SIMP_D}}
{\red{SIMP_B} \cdot \green{SIMP_N}}
= \blue{SOLUTION}
person(1) can do SOLUTION different types of exercise per workout.