\log n!
is:
\Omega(n \log n)
\Omega(n^2)
\Omega(n)
\Omega(\log n)
\Omega(n^n)
It should be obvious that
\log n! < \log n^n = n \log n
.
So that eliminates anything bigger
than n \log n
.
There are n
terms in n!
, and
you need to take the log of each of them. Since they have
some size, it has to be much more than
\log n
.
It turns out to be worse than just n
.