The total number of pairs of records
among n
records is:
n(n-1)/2
n^2/2
n
2n
2n^2
n \log n
n!
n!/2
n(n+1)/2
There are n
ways to pick the first record in
the pair.
This leaves n-1
ways to pick the second
record.
We consider pair (A, B) to be the same as pair (B, A).