Khan.randRange(6, 10) Khan.randRange(numV, (numV * (numV - 1))/2) Khan.randRange(4,6) Khan.randRange(2,4) numV * numV * 1

WARNING! Read the conditions for the problems in this set very carefully!

Assume for a directed graph with numV vertices and numE edges that a vertex index requires vertB bytes, and a pointer requires pointerB bytes. The graph is unweighted, so assume that each matrix element stores one byte to represent the edge. Calculate the byte requirements for an adjacency matrix.

ANS

The matrix is |V| by |V|

Each position of the matix needs 1 byte

V^2 * 1 bytes = ANS